Answer:

• A ball is nearly 20 marbles. • An eraser is nearly 2 marbles. • A lemon is nearly 4 marbles. • A pencil is nearly 2 marbles. • A potato is nearly 10 marbles.

Disclaimer: The answer may vary from student to student. The answers provided here are for reference only.

Answer:

Disclaimer: The answer may vary from student to student, based on his/her observation. It is highly recommended that the students prepare the answers on their own. The answers provided here are for reference only.

Answer:

Disclaimer: The answer may vary from student to student, based on his/her observation. It is highly recommended that the students prepare the answer on their own.

Answer:

1) Volume of 1 Math-Magic book = 540 cm cubes. 5 Math-Magic books are used to make the stage. So, volume of the stage = Volume of 5 such Math-Magic books = 5

×540 cm cubes = 2700 cm cubes

2)• A matchbox is about 13.5 cm cubes. • A geometry box is about 157.5 cm cubes. • An eraser is about 1.5 cm cubes.

We will multiply the length, breadth and height of the object to cross-check our guess.

Answer:

• Number of matchboxes in 1 layer = 14 Number of layers that make the stage = 4 Total number of matchboxes in 4 layers =

14 × 4                                                                    = 56

• Volume of 1 matchbox = 10 cm cubes A total of 56 matchboxes are used to make the stage. So, the volume of this stage = 56

×10 cm cubes = 560 cm cubes.

• Now, let’s assume length of matchbox is 4.5 cm. All the matchboxes are arranged in a line. Then the total length of the line made by all 56 matchboxes = 4.5 cm

×56 = 252 cm

• The volume of Math-Magic book is 540 cm cubes, whereas volume of the platform is 560 cm cubes. Thus, Tanu’s platform has more volume as compared to Math-Magic book.

•

The volume of each platform is equal to 56 matchboxes.

Disclaimer: The length, width and height of the platform varies from student to student, based on his/her observation. It is highly recommended that the students prepare the answer on their own.

Answer:

• In the bottom layer, we can see that there are 4 matchboxes in length and 4 in breadth. So, the bottom layer has 16 matchboxes.

In the layer above the bottom, we can see that there are 3 matchboxes in length and 3 in breadth. So, the layer above bottom has 9 matchboxes.

Now, the second layer from the top has 2 matchboxes in length and 2 matchboxes in breadth. So, this layer has 4 matchboxes.

The top layer has only 1 matchbox. Thus, total volume of the arrangement in terms of matchboxes = 16 + 9 + 4 + 1 = 30

Disclaimer: The answer may vary from student to student, based on his/her observation. It is highly recommended that the student prepare the answer on their own.

Answer:

(a) Length of the side of the cube = 7 cm

(b) Number of centimeter cubes that can be arranged along its: • Length?  7  • Width?  7  • Height?  7 

(c) Answer Thimpu’s questions: To make the first layer on the table, I use 49 cubes. I need 7 such layers to make the cube.

(d) So the total cm cubes =  7

×7

×7 = 343

(e) The volume of the paper cube is the same as 343 cm cubes.

Answer:

Length of the side of paper cube = 7 cm Length of the side of Anan’s cube = 2 × 7 cm = 14 cm

We can fit 4 paper cubes, each of side 7 cm in the first layer of the big cube. As the length of each side of the big cube is 14 cm, there will be a total of 2 layers with each layer containing 4 paper cubes.

So, number of paper cubes in 2 layers = 2 â€‹× 4 = 8

Thus, 8 paper cubes will fit inside the Anan’s big cube.

Answer:

• I guess that the cubes will fit in all the 3 boxes put together. Dinga’s guess is correct.

• First of all, we will find how many cubes each box will contain, and then all the cubes will be added together to cross-check the guess.

• In the first layer of box B, we can keep 11

×11 = 121 cubes. There are 10 such layers. So, in box B, we can arrange 10

×121 = 1210 cubes

• In the first layer of box C, we can keep 15

×9 = 135 cubes. There are 10 such layers. So, in box C, we can arrange 10

×135 = 1350 cubes

• In all the three boxes we can arrange 1200 + 1210 + 1350 = 3760 cubes So, 3760 centimetre cubes in total can be packed in three boxes.

Disclaimer: The first two part of the answer may vary from student to student. The answers provided here are for reference only.

Answer:

Disclaimer: The answer may vary from student to student, based on his/her observation. It is highly recommended that the students prepare the answer on their own.

Answer:

(a) • Rice required per person per day = 100 g Flour required per person per day = 100 g Total rice and flour required for each person for a single day = 200 g Thus, for 6 days, rice and flour required per person = 200 g

×6 = 1200 g

• Pulses required per person per day =

13the weight of rice and flour Pulses required per person for  days = 1200 g

× 13                                                               = 400 g

• Dried onions required per person per day = 10 g For 6 days, dried onions required per person = 6

×10 g = 60 g

(b) On drying 1 kg fresh tomatoes, we get 100 g of dried tomatoes. 1 kg = 1000 g It means for 100 g dried tomatoes, we need 1000 g of fresh tomatoes.

So, for 1 g dried tomato, we need

1000100 = 10g fresh tomatoes.

Hence, for 10 g dried tomatoes, we need 10

×10 g = 100 g fresh tomatoes.

Thus, for 6 days, we need to dry 6

×100 g = 600 g of fresh tomatoes.

(c) Total weight of food in each person’s bag = 600 g + 600 g + 300 g + 50 g

×6 + 50 g

×6 + 40 g

×6 + 10 g

×6 + 40 g

×6 + 5 g

×          6 + 10 g

×6 + 10 g

×6 =2790 g

Answer:

• Weight of a child of my age = 30 kg Weight of an elephant = 5000 kg Total number of children weighing 5000 kg   =

500030                                                                            = 167 (approximately)

•  Weight of a baby elephant = 90 kg My weight at birth             = 3 kg Number of times a baby elephant was heavier than me at birth =

903                                                                                                          = 30 So, the baby elephant was 30 times heavier than me at birth.

•  Food eaten by a grown up elephant in 1 day    = 136 kg Food eaten by a grown up elephant in 30 days = 30

×136 = 4080 kg

In a year, it will eat around 50,000 kg of food.

Answer:

1 kg = 1000 g Weight of a 5 rupee coin = 9 g

(a) Weight of 18 kg sack in grams           = 18

×1000 = 18000 g Number of 5 rupee coins in 18 kg sack = 18000 ÷ 9 = 2000

(b) Weight of 54 kg of sack in grams          = 54

×1000 = 54000 g Number of 5 rupee coins in 54 kg sack = 54000 ÷ 9 = 6000

(c) Weight of sack                                         = 4500 g Number of 5 rupee coins in 4500 g sack = 4500 ÷ 9 = 500

(d) Weight of 2 kg 250 g sack = 2

×1000 g + 250 g = 2000 g + 250 g = 2250 g Number of 5 rupee coins in 2250 g sack = 2250 ÷ 9 = 250

(e) Weight of 1 kg 125 g sack = 1

×1000 g + 125 g = 1000 g + 125 g = 1125 g

Number of 5 rupee coins in 1125 g sack = 1125 ÷ 9 = 125

•   We know, 1 kg = 1000 g Weight of a 2 rupee coin = 6 g

(a) Now, weight of sack with 2200 coins = 2200

×6 = 13200 g = 13

×1000 g + 200 g = 13 kg 200 g

(b) Weight of the sack with 3000 coins = 3000

×6 = 18000 g Thus, 18000 g = 18

× 1000 g = 18 kg

• Weight of 100 one-rupee coins = 485 g So, weight of a single one-rupee coin =

485100= 4.85 g Thus, weight of 10000 one-rupee coins = 10000

×4.85 = 48500 g

So, 48500 g = 48

× 1000 g + 500 g = 48 kg 500 g

Answer:

• The people who cannot see, make out different notes and coins, by remembering the shapes and sizes of different notes and coins.
• To check if a 100 rupee note is real or fake, we should see the size, quality of paper, and printing or the style in which the numbers are written on the note.